Aidez moi l'exercice 28

(x+1)[(5x-1)-(3x-12)]=0
(x+1)(5x-1-3x+12)=0
(x+1)(2x+11)=0

x+1=0
x=-1

2x+11=0
2x=-11
x= [tex] -\frac{11}{2} [/tex]

1)
(x+1)(5x-1)-(x+1)((3x-12) = 0  on met x+1 en facteur
⇔(x+1)(5x-1-3x+12) = 0
⇔(x+1)(2x+11) = 0

2
(x+1)(2x+11) = 0
⇔ x+1 = 0 ou 2x+11 = 0
⇔ x = -1 ou 2x = -11
⇔ x = -1 ou x = -11/2