développer et simplifier l'expression : A= -5x-(3-2x)² + (2x²+5) factoriser l'expression: D= 3x(x-1)+2x E= (x-6)(x+2)-(x-6)(2x+3) F= (x-1)²+(2x-3)(x-1) G= (x-1)

A= -5x-(3-2x)² + (2x²+5)
A = -5x-(9-12x+4x²) +2x²+5
A = -5x-9-12x-4x²+2x²+5
A = -2x²-17x-4

factoriser l'expression:
D= 3x(x-1)+2x    on met x en facreur
D = x(3(x-1)+2)

E= (x-6)(x+2)-(x-6)(2x+3)   on met x-6 en facteur
E = (x-6)(x+2-2x-3)
E = (x-6)(-x-1)

F= (x-1)²+(2x-3)(x-1)       on met x-1 en facteur
F = (x-1)(x-1+2x-3)
F =(x-1)(3x-4)

G= (x-1)²-(2x-3)(x-1)   on met x-1 en facteur
G = (x-1)(x-1-2x+3)
G = (x-1)(-x+2)

H= (2x-1)²-(x+2)²      a²-b² = (a+b)(a-b)
H = (2x-1+x+2)(2x-1-x-2)
H = (3x+1)(x-3)

A=-5x-(3-2x)²+(2x²+5)
A=-5x-(9-12x+4x²)+(2x²+5)
A=-5x-9-12x-4x²+2x²+5
A=-2x²-17x-4

D=3x(x-1)+2x
D=x(3(x-1)+2)

E=(x-6)(x+2)-(x-6)(2x+3)
E=(x-6)(x+2-2x-3)
E=(x-6)(-x-1)

F=(x-1)²+(2x-3)(x-1)
F=(x-1)(x-1+2x-3)
F=(x-1)(3x-4)

G=(x-1)²-(2x-3)(x-1)
G=(x-1)(x-1-2x+3)
G=(x-1)(-x+2)

H= (2x-1)²-(x+2)² --> identité remarquable
H = (2x-1+x+2)(2x-1-x-2)
H = (3x+1)(x-3)

J'espère t'avoir aidé !